Question

${4}^{x + 1} = 64 \: then \: the \: value \: of \: x$
​

Answer 1

$\huge\tt\colorbox{pink}{αղsաҽɾ}$

${4}^{x + 1} = 64 \\ \\ = > {4}^{x + 1} = {4}^{3} \\ \\ = > x + 1 = 3 \\ \\ = > x = 3 - 1 \\ \\ = > x = 2$

$concept \: used \\ \\ {a}^{m} = {a}^{n} \\ \\ = > m = n$

$\tt\red{☦ mark - me - as - brainliest ☦}$