Math, asked by akatepallewar, 6 months ago

4^{x-1\\} = 32^{x-1} . What is the value of x?

Answers

Answered by shashankrana1678
1

Answer:

1

Step-by-step explanation:

(2)^(2)(x-1) = (2)^(5)(x-1)

(2)^2x-2    = (2)^5x-5

now,

2x-2 = 5x-5

2x - 5x = -5 + 2

- 3x =-3

x = -3 / -3

x=1

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