Question

$4 {x}^{2} + 4x + 1 = 0$
pls help me to find the answer using quadratic Equations​

Answer 1

${4x}^{2} + 4x + 1 = 0 \\ \\ {4x}^{2} + 2x + 2x + 1 = 0 \\ \\ 2x(2x + 1) + 1(2x + 1) = 0 \\ \\ (2x + 1)(2x + 1) = 0 \\ \\ 2x + 1 = 0 \\ 2x = - 1 \\ x = \frac{ - 1}{2}$

❗❗❗❗❗❗❗❗ Mark as brainliest ❗❗❗❗❗❗❗❗