Math, asked by sathyanethaji20, 10 months ago


4 {x}^{2} (x - 1) - 6 {x}^{3} (x {}^{2}  - 1)

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Answered by CUTEB0Y
3

Answer:

 {4x}^{2} (x - 1) - 6  {x}^{3} ( {x}^{2}  - 1) \\  \\  {4x}^{3 }  -  {4x}^{2}  -  {6x}^{5}  -  {6x}^{3}  \\  \\  - 4 {x}^{2}  - 2 {x}^{3}  - 6 {x}^{5}

Take minus comman

 - (4 {x}^{2}   +  {2x}^{3}  + 6 {x}^{5} )

Answered by Satyamrajput
6

4x^2(x-1)-6x^3(x^2-1)

=> 4x^3-4x^2-6x^5+6x^3

=>10x^3-4x^2-6x^5

=>-4x^2-6x^5+10x^3

=>-2x^2-3x^5+5x^3

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