Question

${4}^{x} } = {3}^{y} = {12}^{ - z \\ } \: find \frac{1}{x} + \frac{1}{y} + \frac{1}{z}$
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Answer 1

$\mathcal \orange{SOL:-}$

$\tt {4}^{x} = {3}^{y} = {12}^{ - z} \\ \\ \tt \implies \: x \: = y \: = - z \\ \\ \tt \: \implies \: x \: = y \: = \frac{1}{z} \\ \\ \tt \: \implies \: \frac{1}{x} \: = \frac{1}{y} \: = z \\ \\ \tt \: \red{now} \: \: \: \frac{1}{x} + \frac{1}{y} + \frac{1}{z} \\ \\ \tt \: \implies \: z \: + \: z \: + \frac{1}{z} \\ \\ \tt \: \implies \: \: 2z \: + \: \frac{1}{z} \\ \\ \tt \: \implies \: \frac{ 2{z}^{2} + 1 } {z}$

Answer 2

Step-by-step explanation:

your answer is 2z²+1/z