Question

$4 {y }^{2} - 4y + 1$
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Answer 1

$4y^2-4y+1=0\\4y^2-2y-2y+1=0\\2y(2y-1)-1(2y-1)=0\\(2y-1)(2y-1)=0\\y=1/2$

Answer 2

Given

4y² - 4y + 1

solve it

Solution

Solve this by splitting middle term

=> 4y² - 4y + 1

=> 4y² - 2y - 2y + 1

=> 2y(2y -1) -1(2y - 1)

=> (2y -1)(2y-1)

We can also find zeros

=> 2y - 1 = 0

=> 2y = 1

=> y = 1/2

Above equation has same zeros i.e 1/2