Question

$40 - 16(3m - 5) = - 10(4m - 8)$​

Answer 1

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Q:-solve and find the value of m and hence verify

$40 - 16(3m - 5) = - 10(4m - 8)$

$\huge\tt\underline\blue{Answer }$

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$⟹\bold{40 - 16(3m - 5) = - 10(4m - 8)}$

$⟹\bold{40 - 48m + 80 = - 40m + 80}$

$⟹\bold{40 + 80 - 48m = - 40m + 80}$

$⟹\bold{120 - 48m = - 40m + 80}$

$⟹\bold{120 - 80 = - 40m + 48m}$

$⟹\bold{40 = 8m}$

$⟹\bold{\red{m = \frac{40}{8} = 5}}$

$\mathcal{CHECK:-}$

$⟹\bold{40 - 16(3(5) - 5) = - 10(4(5) - 8)}$

$⟹\bold{40 - 16(15 - 5) = - 10(20 - 8)}$

$⟹\bold{40 - 16(10) = - 10(12)}$

$⟹\bold{40 - 160 = - 120}$

$⟹ \bold{- 120 = - 120}$

Therefore,L.H.S=R.H.S

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Answer 2

Step-by-step explanation:

40-16(3m-5)=-10(4m-8)

40-48m + 80 = -40m + 80

120- 48m =-40m +80

on transposing 80 to L.H.S and -48m to R.H.S side.

120 -80 = 48m - 40m

40 = 8m

dividing both side by 8

5 = m

then answer ,

m = 5

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