Question

$42. x ^ 2 + 5x - (a ^ 2 + a - 6) = 0 \\ \\ pls \: solve \: this \: qestion \: fast$
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Answer 1

Answer:

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Answer 2

Step-by-step explanation:

$\bf{x }^ 2 + 5x - ({a }^ 2 + a - 6) = 0 \\ \\ \tt \implies \: x(x + 5) = {a }^{2} + a - 6 \\ \\ \tt \implies \: x(x + 5) = {a}^{2} + 3a - 2a - 6 \\ \\ \tt \implies \: x(x + 5) = (a + 3) - 2(a + 3) \\ \\ \tt \implies \: x(x + 5) = (a + 3)( a- 2)\\\\ x \:\tt \implies (a+3),(a-7)$