Question

$( - 4a) \ \times ( - 3a2bc)$
​

Answer 1

Answer:

We know that,

The coefficient of the product of two monomials is equal to the product of their coefficients. And the variable part in the product of two monomials is equal to the product of the variables in the given monomials.

∴(−4ab)×(−3a

2

bc)

=(−4×−3)×(a×b×a

2

×b×c)

=(−4×−3)×(a×a

2

)×(b×b)×c

=(12)×(a

1+2

)×(b

1+1

)×c[∵a

m

×a

n

=a

m+n

]

=(12)×(a

3

)×(b

2

)×c

=12 a

3

b

2

c