Question

$4m {}^{2} - 169n {}^{2} \div 2m + 13n$
Simplify​

Answer 1

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Answer 2

Answer:

$\red { \frac{4m^{2}-169n^{2}}{2m+13n}}\green{=(2m-13n)}$

Step-by-step explanation:

$\red { \frac{4m^{2}-169n^{2}}{2m+13n}}$

$= \frac{(2m)^{2}-(13n)^{2}}{(2m+13n)}$

$= \frac{(2m+13n)(2m-13n)}{(2m+13n)}$

$\boxed {\pink { a^{2}-b^{2}= (a+b)(a-b)}}$

$= (2m-13n)$

Therefore.,

$\red { \frac{4m^{2}-169n^{2}}{2m+13n}}\green{=(2m-13n)}$

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