Math, asked by sameerchaudhari2106, 9 months ago


4n {}^{2}  - 51n - 13 = 0

Answers

Answered by Anonymous
0

Step-by-step explanation:

4 {n}^{2}  - 51n - 13 = 0 \\  \\ 4 {n}^{2}  - 52n + n - 13 = 0 \\  \\ 4n(n - 13) +1 (n - 13) = 0 \\  \\ (4n + 1)(n - 13) = 0 \\  \\ 4n + 1 = 0 \:  \: \: or \:  \:  \: n - 13 = 0 \\  \\ n =  \frac{ - 1}{4}  \:  \:  \:  \: or \:  \:  \:  \: n = 13

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