Question

$4x + 1 \div 3 + 3x + 1 \div 2 = 3x - 7 \div 4 + 13$
Solve the following equation​

Answer 1

Answer:

21/5

Step-by-step explanation:

Take LCM

8x+2+9x+3/6 = 3x-7+52/4

17x+5/6 = 3x+45/4

17x+15/3 = 3x+45/2

cross multiply

34x+30 = 9x + 135

25x = 105

5x = 21

x = 21/5

Answer 2

QUESTION:

${\orange{\frac{4x + 1}{3} + \frac{3x + 1}{2} = \frac{3x - 7}{4} + 13}}$

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SOLUTION:

$\frac{4x + 1}{3} + \frac{3x + 1}{2} = \frac{3x - 7}{4} + 13$

$\frac{4x + 1}{3} + \frac{3x + 1}{2} - \frac{3x - 7}{4} = 13$

$\frac{4(4x + 1) + 6(3x + 1) - 3(3x - 7)}{12} = 13$

$16x + 4 + 18x + 6 - 9x + 21 = 13 \times 12$

$25x + 31 = 156$

$25x = 156 - 31$

$25x = 125$

$x = \frac{125}{25}$

${\blue{x = 5}}$

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${\large{\mathcal{\red{Have \: a \: nice \: day \: ahead}}}}$