![4x \: + 11(2 + x) = 50 4x \: + 11(2 + x) = 50](https://tex.z-dn.net/?f=4x+%5C%3A+%2B+11%282+%2B+x%29+%3D+50)
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4x+11(2+x)=50
Solution:
or,4x+22+11x=50
or,15x=50-22
or,15x=28
Therefore,x=28/15
Solution:
or,4x+22+11x=50
or,15x=50-22
or,15x=28
Therefore,x=28/15
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![](https://hi-static.z-dn.net/files/dfe/3c7f27b93bd15e0f6cc423ea89cb9758.png)
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