Question

$4x^{2} - 15x - 4$
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Answer 1

$\tt\:\implies 4x^{2} - 15x - 4 = 0$

$\tt\:\implies 4x^{2} - x + 16x - 4 = 0$

$\tt\:\implies x(4x - 1) + 4(4x - 1) = 0$

$\tt\:\implies (4x - 1)(x + 4) = 0$

$\tt\:\therefore x = \frac{1}{4} ; x = - 4$

Hope it helps you...

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Answer 2

Answer:

4x²-15x-4

➪4x²-(16-1)x-4

➪4x²-16x+x-4

➪4x(x-4)+1(x-4)

➪(x-4)(4x+1)

Hope it will help you......☺️