Question

${4x }^{2} + 27x + 35$
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Answer 1

$= > 4x {}^{2} + 27x + 35 = 0 \\ = > 4x {}^{2} + 20x + 7x + 35 = 0 \\ = > 4x(x +5 ) + 7(x + 5) = 0 \\ = > (4x + 7)(x + 5) = 0 \\ = > 4x + 7 = 0 \\ = > 4x = - 7 \\ = > x = - \frac{7}{4} \\ \\ or \\ \\ = > x + 5 = 0 \\ = > x = - 5 \\ \\ hence \: \: (x = - \frac{7}{4} \: \: \: - 5)$

I hope that helps you

Answer 2

❣️$\textbf{\large{\pink{\underline{\underline{Step by step Explanation:-}}}}}$

Mate,, you did not say to wt that do..But I think I have to factories it..

$\mathrm{{4x }^{2} + 27x + 35}$

$\mathrm{\implies{{4x }^{2} + 20x+7x + 35}}$

$\mathrm{\implies{4x(x + 5)+7(x + 5)}}$

$\mathrm{\implies{(x + 5)(4x+7)}}$

❣️$\textbf{\small{\red{\underline{Hope it helps you..}}}}$❣️

$\textit{\small{\green{\underline{Please mark it as Brainliest answer.. thanks..}}}}$