Question

$4x {}^{2} - 2x - 8 = 0$
nature of solutions​

Answer 1

SOLVE :

${4x}^{2} - 2x - 8 = 0$

SOLUTION:

$x1 = \frac{( - 2) - \sqrt{ {( - 2)}^{2} } - 4 \times 4 \times ( - 8)}{2 \times 4} \\ = \frac{2 - 2 \sqrt{32} }{8} \\ = - 1.186$

________________________________

$x2 = \frac{( - 2) + \sqrt{ {( - 2)}^{2} - 4 \times 4 \times ( - 8) } }{2 \times 4} \\ = \frac{2 + 2 \sqrt{33} }{8 } \\ = 1.686$

$\huge\boxed{\fcolorbox{cyan}{pink}{ANSWER:}}$

$\boxed{x1=-1.186}$

$\boxed{x2=1.686}$