Math, asked by pampanaskar2019, 12 days ago


(4x ^{2}  + 3x +  \frac{1}{2}  )\div(2x + 1)
please expand it.​

Answers

Answered by sagarkadadevar20
0

Step-by-step explanation:

(4x²+3x+1/2)÷(2x+1)

= (4x²+x+2x+1/2)÷(2x+1)

= x(4x+1)+(4x+1)/2÷(2x+1)

=x(4x+1)+1/2(4x+1)÷(2x+1)

= (x+1/2)(4x+1)÷(2x+1)

= (2x+1÷2)(4x+1)÷(2x+1)

=(2x+1)(4x+1)÷(2x+1)×2

=(4x+1)÷2

Similar questions