Question

$4x ^{2} - 8x + 3$

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Answer 1

Step-by-step explanation:

$\huge\underline{\underline{\sf ANSWER}} \\ \\ 4 {x}^{2} - 8x + 3 \\ a = 4 \\ b = - 8 \\ c = 3 \\ Using \: formula \: Method => \\ \\ x = \frac{ - b + \: or \: - \sqrt{ {b}^{2} - 4ac } }{2a} \\ x = \frac{8 + \: or \: - \sqrt{64 - 48} }{2(4)} \\ x = \frac{8 + \: or \: - \sqrt{16} }{8} \\ x = \frac{8 + \: or \: - 4}{8} \\ x = \frac{3}{2} \: \: \: \: \: or \: \: \: \: x = \frac{1}{2}$

Answer 2

$4 {x}^{2} - 8x + 3 = 4 {x}^{2} - 2x - 6x + 3 \\ = 2x(2x - 1) - 3(2x - 1) \\ = (2x - 3)(2x - 1)$

Product = c×a = 4×3 =12

Sum = b = -8

Therefore required nos are -6 and -2

Product = -6×-2 =12

Sum = -6-2=-8

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