Question

$4x {}^{2} + 9y {}^{2} = 16xy$

show that
$2 log_{}(2x - 3y) = 2 log2 + logx + logy$

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Answer 1

Answer:

Step-by-step explanation:

4x²+9y² = 16xy

4x²+9y²-16xy = 0

4x² - 12xy +9y²-4xy=0

(2x-3y)²-4xy=0

(2x-3y)² = 4xy

log(2x-3y)² = log4xy

2log(2x-3y)=log2² + logx+logy

2log(2x-3y)=2log2+logx+logy