Question

$4x { }^{2} + x - 3$
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Answer 1

$\huge\mathfrak{Answer:-}$

$\sf 4x{}^{2}+x-3$

$\sf 4x{}^{2}+(4-3)x-3$

$\sf 4x{}^{2}+4x-3x-3$

$\sf 4x(x+1)-1(x+1)$

$\sf (x+1)(4x-1)$

$\mathfrak{FOR \:zeros }$

¡) $\mathfrak {x+1=0}$

$\mathfrak{x=(-1)}$

¡¡)$\mathfrak {4x-1=0}$

$\mathfrak {4x=1}$

$\mathfrak {x=\frac{1}{4}}$

$\mathfrak {x=(-1),\frac{1}{4}}$

Answer 2

Step-by-step explanation:

${4x}^{2} + x - 3 \\ = {4x}^{2} + 4x - 3x - 3 \\ = 4x(x + 1) - 3(x + 1) \\ = (x + 1)(4x - 1) \\ = x = - 1or \frac{1}{4}$