Math, asked by skbxr211, 9 months ago

$4y + 1 \div 3 + 2y - 1 \div 2 - 3y - 7 \div 5 = 47 \div 10 \\$

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Answered by ItzParth14

2

Answer:

$[tex]4y + 1 \div 3 + 2y - 1 \div 2 - 3y - 7 \div 5 = 47 \div 10 \\$ [/tex]

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