Question

$5^{-1} - 6^{-1}$ evaluate with steps

Answer 1

Answer:

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Step-by-step explanation:

Let's study another example.

Evaluate \dfrac13a-1-\dfrac12b

3

1

a−1−

2

1

bstart fraction, 1, divided by, 3, end fraction, a, minus, 1, minus, start fraction, 1, divided by, 2, end fraction, b when a=12a=12a, equals, 12 and b=6b=6b, equals, 6.

\begin{aligned} &\phantom{=}\dfrac13\blueD a-1-\dfrac12\goldD b \\\\ &= \dfrac13 \cdot \blueD {12}-1-\dfrac12 \cdot \goldD 6~~~~~~~~\text{Replace }\blueD{a} \text{ with } \blueD{12}\text{ and } \goldD b \text{ with } \goldD 6\text{.} \\\\ &=4 - 1 - 3 \\\\ &=0 \end{aligned}

=

3

1

a−1−

2

1

b

=

3

1

⋅12−1−

2

1

⋅6 Replace a with 12 and b with 6.

=4−1−3

=0

Answer 2

Step-by-step explanation:

first change exponents to positive, by that base will be reciprocated. then it becomes 1/5 - 1/6 = 6/30 - 5/30 = 1/30

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