Question

(
$(5 {}^{5} + 0.01) {}^{2} - (5 {}^{5} - 0.01) {}^{2} {}^{} = 5 {x}^{}$
​

Answer 1

we have,

(a+b)2−(a−b)2

=> a2+b2+2ab−a2−b2+2ab

=> 4ab

put the value of a and b, we have

4∗55∗0.01

=125.

hope it helped you

Step-by-step explanation:

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