solve this question
Answers
Answered by
0
Answer:
Q2) Solve the following equations:
(a) 2(x + 4) = 12 (b) 3(n – 5) = 21 (c) 3(n – 5) = – 21
(d) – 4(2 + x) = 8 (e) 4(2 – x) = 8
Solution 2:
(a) 2(x+4)= 12
x+4\ =\ \frac{12}{2}x+4 = 212
x+4 = 6
x= 6-4
x= 2
(b) 3(n-5) = 21
n-5\ =\ \frac{21}{3}n−5 = 321
n-5 = 7
n = 7+5
n = 12
(c) 3(n-5) = -21
n-5\ =\ -\frac{21}{3}n−5 = −321
n-5 = -7
n= -7+5
n = -2
(d) 3-2 (2-y) = 7
-2 (2-y) = 7-3
-2(2-y) = 4
2-y\ =\ \frac{4}{2}2−y = 24
2-y = 2
-y = 2 -2
y = 0
(e) 4(2-x) = 9
-4\times2-x\times\left(-4\right)\ =\ 9−4×2−x×(−4) = 9
-8+4x = 9
4x= 9+8
x=\ \frac{17}{4}x= 417
Still have questions? Our expert teachers can help you out
Book a free class now
Answered by
0
Answer:
5/2 + 6/5
LCM = 10
25/10 + 12/10 = 37/10
Similar questions