Question

$5a {}^{2} + 14a - 3$

Answer 1

$\textbf{Your answer }$ ...❗❗

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$5a {}^{2} + 14a - 3 = 0 \\ \\ \\ 5 a {}^{2} + 15a - a - 3 = 0 \\ \\ \\ Taking \: commons \\ \\ \\ 5a ( a + 3 ) - 1 ( a + 3 ) = 0 \\ \\ \\ 5a - 1 = 0 , a + 3 = 0 \\ \\ \\ a = (\frac{1}{5}) , a = - 3$

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Answer 2

$5a {}^{2} + 14a - 3 = 5a {}^{2} + (15 - 1)a - 3 \\ = 5a {}^{2} + 15a - a - 3 \\ = 5a (a + 3) - 1(a + 3) \\ = (a + 3)(5a - 1)$

If you want to find the values of a....Then
$5a {}^{2} + 14a - 3 = 0 \\ = > (a + 3)(5a - 1) = 0$

So,


a+3=0

=>a= -3

Or,

5a-1=0

=>5a= 1

=>a=1/5


Hence,

The values of a are -3 , 1/5