Question

$5a {}^{3} + 11a {}^{2} + 4a {}^{2} - 2$
plz help me to factorise this polynomial.I will follow u mark as brainliest
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Answer 1

Step-by-step explanation:

a2" was replaced by "a^2". 1 more similar replacement(s).

(((5 • (a3)) + 11a2) + 4a) - 2

((5a3 + 11a2) + 4a) - 2

5a3+11a2+4a-2 is not a perfect cube

The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms

In our case this means that

5a3+11a2+4a-2

can be divided with a+1

Polynomial Long Division

Dividing : 5a3+11a2+4a-2

("Dividend")

By : a+1 ("Divisor")

dividend 5a3 + 11a2 + 4a - 2

- divisor * 5a2 5a3 + 5a2

remainder 6a2 + 4a - 2

- divisor * 6a1 6a2 + 6a

remainder - 2a - 2

- divisor * -2a0 - 2a - 2

remainder 0

Quotient : 5a2+6a-2 Remainder: 0

(5a2 + 6a - 2) • (a + 1) is ur answer

Answer 2

Answer:

(5a2 +6a -2).a+1 is ur answer