Question

$5m {}^{2} + 2m + k = 0 \: find \: the \: value \: of \: k.$

Answer 1

$(5m {}^{2} + 2m + k) \div k = 0 \div k \\ 5m { }^{2} + 2m \div k = 0 \\ 5m {}^{2} + 2m = 0 \times k = 0 \\ m(5m + 2) = 0 \\ 5m + 2 = 0 \\ m = - 2 \div 5$
putting the value of m
5 (-2/5)^2+2 (-2/5)+k=0
4/5-4/5+k=0
k=0
I M NOT SURE ABOUT THE SOLUTION