Question

$5x {}^{2} - 7x - 6 = 0$
find the roots of the following quadratic equation by completing square method​

Answer 1

Step-by-step explanation:

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factorize:

$5 {x}^{2} - 7x - 6$

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$divide \: the \: equation \: by \: 5$

${x}^{2} - \frac{7x}{5} - \frac{6}{5}$

$( {x}^{2} - (2)(x)( \frac{7}{2 \times 5} ) + { \frac{7}{10} }^{2} ) - { \frac{7}{10} }^{2} - 6$

${ (x - \frac{7}{10} )}^{2} - \frac{49}{100} - \frac{600}{100}$

${(x - \frac{7}{10} )}^{2} - \frac{649}{100}$

${(x - \frac{7}{10} )}^{2} = \frac{649}{100}$

$( x - \frac{7}{10} ) = \sqrt{ \frac{649}{100} }$

$x = 2.54 + \frac{7}{10} \\ x = - 2 .54 + \frac{7}{10}$

solve further you will get the values of x