Math, asked by sandippatil02589sp, 9 months ago


 {5y}^{2 }  - 2y - 3

Answers

Answered by dhmakaqueen
2

Answer:

Hey frnd..

Here is ur ans. .

Step-by-step explanation:

5 {y}^{2}  - 2y - 3 = 0 \\ 5 {y}^{2} - 5y + 3y - 3 = 0 \\ 5y(y - 1) + 3(y - 1)  = 0\\ (5 y + 3)(y - 1) = 0 \\ y =  \frac{ - 3}{5}  \: or \: 1

Hope this helps u...

Answered by Fifth
0

5y² - 2y - 3  (middle term splitting where -2 is the sum and -15 is the                                                      product)

5y² + 3y - 5y - 3  

y (5y+3) - 1 (5y+3)

(5y+3) (y-1)

HOPE THIS HELPS ^_^

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