Question

$5y²±5y-10 = 0$

Answer 1

$5 {y}^{2} + 5y - 10 = 0 \\ 5 {y}^{2} + 10y - 5y - 10 = 0 \\ 5y(y + 2) - 5(y + 2) = 0 \\ (y + 2)(5y - 5) = 0$

And

$5 {y}^{2} - 5y - 10 = 0 \\ 5 {y}^{2} - 10y + 5y - 10 = 0 \\ 5y(y - 2) + 5(y - 2) = 0 \\ (y - 2)(5y + 5) = 0$

hope it will help u ✨☺️

Answer 2

Answer:

5y²±5y-10=0

divide the whole equation by 5

y²±y-2=0

• y²+y-2=0 and
• y²-y-2=0

y²+y-2=0

y²-y+2y-2=0

y(y-1)+2(y-1)=0

(y-1)(y+2)=0

y=1,-2

y²-y-2=0

y²+y-2y-2=0

y(y+1)-2(y+1)=0

(y+1)(y-2)=0

y=-1,2