Question

$(6 { }^{ - 1} - 8 {}^{ - 1} ) =$
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Answer 1

Answer:

$24^{-1}$

Step-by-step explanation:

$(6^{-1}-8^{-1})$

= $\frac{1}{6} - \frac{1}{8}$

= $\frac{4}{24} - \frac{3}{24}$ (The LCM of the denominators 6 and 8 is 24)

= $\frac{4-3}{24} = \frac{1}{24} = 24^{-1}$

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Answer 2

Answer:-

$(6 { }^{ - 1} - 8 {}^{ - 1} )$

$= (\frac{1}{6} - \frac{1}{8} )$

LCM of 6 and 8 = 48

(now let's convert both the denominators to 48)

$∴ \frac{1}{6} = \frac{1 \times 8}{6 \times 8} = \frac{8}{48}$

$\frac{1}{8} = \frac{1 \times 6}{8 \times 6} = \frac{6}{48}$

So now we have both the denominators same

$∴ \frac{8}{48} - \frac{6}{48} = \frac{2}{48}$

$\frac{2}{48} \div 2 = \frac{1}{24}$

(We divided the fraction 2/48 by 2 because both the numerator and the denominator is divisible by the number 2)

$Answer : \frac{1}{24}$

@BengaliBeauty

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