Question

$6 - 9c - {27c}^{2}$
solve question with factorisation method.
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Answer 1

Answer:

$6 - 9c - {27c}^{2} \\ \\ 6 - 18c + 9c - 27 {c}^{2} \\ \\ 6 \times (1 - 3c) + 9c \times (1 - 3c) \\ \\ (1 - 3c) \times (6 + 9c)$

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