Question

$6 - 9e - 27e {?}^{2}$
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Answer 1

Answer:

$\huge{\underline{\underline{Given→}}}$

• $\mathrm\green{→Equation=27e^2+9e+6}$

$\huge{\underline{\underline{To\:Find→}}}$

$\mathrm\purple{→Value\:of\:e\:in\:the\:given\:equation}$

$\huge{\underline{\underline{Answer→}}}$

$\bold{\underline{\underline{\dag{Simplification\dag→}}}}$

${27e}^{2} + 9e + 6 \\ = 3( {9e}^{2} + 3e + 2) \\ = {9e}^{2} + 3e + 2$

$\displaystyle{\boxed{→9e^2+3e+6✔}}$

$\bold{\underline{\underline{Now→}}}$

$\mathrm\blue{→9e^2+3e+2}$

$\mathrm\blue{→9e^2-3e+6e+2}$

$\mathrm\blue{→-3e(-3e+1)-2(-3e-1)}$

$\mathrm\blue{→(-3e+1)(-3e-2)}$

$\mathrm\blue{→e=-\dfrac{1}{3}and\:e=-\dfrac{2}{3}}$

☞ So from here, the value of e=-1/3 and -2/3 which is the required answer.

HOPE IT HELPS.