Question

$6 \sqrt{3} \: x^{2} + 7x - \sqrt{3} = 0$
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Answer 1

Step-by-step explanation:

Given equation is 6√3x²+7x-√3=0

=>6√3x²-2x+9x-√3=0

=>2x(3√3x-1)+√3(3√3x-1)=0

=>(3√3x-1)(2x+1)=0

=>3√3x-1=0 (or) 2x+1=0

=>x=1/3√3 and x=-1/2

Roots are 1/3√3 and -1/2