Question

$6 \sqrt{32} - 8 \sqrt{72} + \sqrt{242} - \sqrt{2}$
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Answer 1

HELLO THERE

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$\sqrt{32} =4\sqrt{2}$

$\sqrt{72} =6\sqrt{2}$

$\sqrt{242} =11\sqrt{2}$

So, the overall sum will be:-

$24\sqrt{2} -48\sqrt{2} +11\sqrt{2} -\sqrt{2}$

$=-14\sqrt{2}$

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HOPE THIS HELPS

Answer 2

$\boxed{\bf{\red{Answer}}}$

$6 \sqrt{32} - 8 \sqrt{72} + \sqrt{242 } - \sqrt{2} \\ \\ 6 \sqrt{2 \times 2 \times 2 \times 2 \times 2 } - 8 \sqrt{2 \times 2 \times 2 \times 3 \times 3} + \sqrt{2 \times 11 \times 11 } - \sqrt{2} \\ \\ 6 \times 2 \times 2 \times \sqrt{2} -8 \times 2 \times 3 \times \sqrt{2} + 11 \times \sqrt{2} - \sqrt{2} \\ \\ 24 \sqrt{2} - 48 \sqrt{2} + 11 \sqrt{2} - \sqrt{2} \\ \\ - 14 \sqrt{2}$

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Hope it helps you ❣