Math, asked by nishant1118, 8 months ago


 6 \sqrt{3x {} ^{2} }  - 47x + 5 \sqrt{3}

Answers

Answered by medhansh88
1

Answer:

6x \sqrt{3}  - 47x + 5 \sqrt{3}

Step-by-step explanation:

6 \sqrt{3 {x}^{2} } - 47x + 5 \sqrt{3}   \\  = 6x \sqrt{3}  - 47x + 5 \sqrt{3}

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