Math, asked by holerajesh, 1 year ago



6 \sqrt{3x ^{2} }  + 7x =  \sqrt{3 }

Answers

Answered by chemistrywala
0

Answer:6√3x^2 -2x +9x -√3 ===

2x(3√3x -1) + √3 ( 3√3x -1)

X== 1/ 3√3 or -√3 /2

Step-by-step explanation:

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