![6 \sqrt{3x ^{2} } + 7x = \sqrt{3 } 6 \sqrt{3x ^{2} } + 7x = \sqrt{3 }](https://tex.z-dn.net/?f=6+%5Csqrt%7B3x+%5E%7B2%7D+%7D++%2B+7x+%3D++%5Csqrt%7B3+%7D+)
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Answer:6√3x^2 -2x +9x -√3 ===
2x(3√3x -1) + √3 ( 3√3x -1)
X== 1/ 3√3 or -√3 /2
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