Question

$6 \sqrt{3x} { }^{2} + 7x = \sqrt{3}$
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Answer 1

Step-by-step explanation:

$6 \sqrt{3 {x}^{2} } + 7x = \sqrt{3}$

$6x \sqrt{3} + 7x = \sqrt{3}$

$x(6 \sqrt{3} + 7) = \sqrt{3}$

$x = \frac{ \sqrt{3} }{6 \sqrt{3} + 7 }$