Question

$6 x {}^{2} - \sqrt{2} x - 2 = 0$
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Answer 1

$\rm 6 x {}^{2} - \sqrt{2} x - 2 = 0$

$\rm 6 x {}^{2} - 3 \sqrt{2} x + 2 \sqrt{2} x - 2 = 0$

$\rm 3 \sqrt{2}x ( \sqrt{2}x - 1) + 2( \sqrt{2} x - 1) = 0$

$\rm (3\sqrt{2}x + \sqrt{2}) (\sqrt{2}x - 1) = 0$

$\rm x =\frac{-\sqrt{2}}{3\sqrt{2}} , x = \frac{1}{\sqrt{2}}$

$\rm x =\frac{-1}{3} , x = \frac{1}{\sqrt{2}}$

Answer 2

→ 6x² - √2x - 2 = 0

Apply quadratic formula & solve the question