Question

$64{x}^{3} - 1$
Factorization by middle term spliting method. ​

Answer 1

Answer:

$64 {x}^{3} - 1 \\ = {(4x)}^{3} - {1}^{3} \\ = (4x - 1) \times ( {(4x)}^{2} + (4x \times 1) + {1}^{2} ) \\ = (4x - 1)(16x ^{2} + 4x + 1) \\ =$