Question

$64a {}^{3} - 27b {}^{3} - 144a {}^{2} b + 108ab {}^{2}$
Please factorise​

Answer 1

$\sf{\red{\boxed{\bold{Solution}}}}$

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$\sf:\implies\:{\bold{ 64a^3 + 27b^3 + 144a^2b + 108ab^2}}$

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$\sf:\implies\:{\bold{ (4a)^3 + (3b)^3 + 144a^2b + 108ab^2}}$

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$\sf:\implies\:{\bold{ (4a)^3 + (3b)^3 + 36ab( 4a + 3b ) }}$

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$\sf:\implies\:{\bold{ (4a)^3 + (3b)^3 + 3\times 4a\times 3b( 4a + 3b ) }}$

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• From identity

$\sf{\red{\boxed{\bold{a^3 + b^3 + 3ab(a+b) = ( a + b)^3}}}}$

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$\sf:\implies\:{\bold{ ( 4a + 3b)^3 }}$

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