Question

$6th \: root \: of \: cube \: of \: 102.$
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Answer 1

Answer:

${102}^{ \frac{1}{2} }$

Step-by-step explanation:

$\sqrt[6]{ {102}^{3} } = {102}^{ \frac{1}{6} \times 3 } = {102}^{ \frac{1}{2} }$

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Answer 2

This is the answer hope it helps