Math, asked by azsxdcfvgb, 1 year ago


 {6x}^{2}  + 37x + 6

Answers

Answered by Divyaalia
5

6 {x}^{2}  + 37x + 6 \\ 6 {x}^{2}  + (36 + 1)x + 6 \\ 6 {x}^{2}  + 36x + x + 6 \\6 x(x + 6) + 1(x + 6) \\ (6x + 1)(x + 6)
Answered by drashti5
7

6 {x}^{2}  + 37x + 6  \\  = 6 {x}^{2} + 36x + x + 6 \\  =6x(x + 6) + 1(x + y) \\  =( 6x + 1)(x + 6)
hope this helps.........
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