Math, asked by shettypraveen381, 3 months ago


6x ^{2} + 5x - 4 = 0

Answers

Answered by Sankalp050
2

Answer:

6 {x}^{2}  + 5x - 4 = 0 \\  \\ 6 {x}^{2}  + 8x - 3x - 4 = 0 \\  \\ 2x(3x + 4) - 1(3x + 4) = 0 \\  \\ (3x + 4)(2x - 1) = 0 \\  \\ x =  \frac{ - 4}{3}  \:  \: or \:  \: x =  \frac{1}{2}

Answered by HAPPYBABY
1

Step-by-step explanation:

6x2+5x−4=0 \\ 6x2+8x−3x−4=02x(3x+4)−1(3x+4)=0 \\ (3x+4)(2x−1)=0 \\ x=3−4orx=21

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