Math, asked by shettypraveen381, 2 months ago

$6x ^{2} + 5x - 4 = 0$

Answers

Answered by Sankalp050

Answer:

$6 {x}^{2} + 5x - 4 = 0 \\ \\ 6 {x}^{2} + 8x - 3x - 4 = 0 \\ \\ 2x(3x + 4) - 1(3x + 4) = 0 \\ \\ (3x + 4)(2x - 1) = 0 \\ \\ x = \frac{ - 4}{3} \: \: or \: \: x = \frac{1}{2}$

Answered by HAPPYBABY

Step-by-step explanation:

$6x2+5x−4=0 \\ 6x2+8x−3x−4=02x(3x+4)−1(3x+4)=0 \\ (3x+4)(2x−1)=0 \\ x=3−4orx=21$

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Answers

$6x ^{2} + 5x - 4 = 0$