Question

$6x ^{2} + 7 \sqrt{2x} + 4 = 0$
​

Answer 1

Answer:

$6x {}^{2} + 7 \sqrt{2} x + 4 \\ 6x {}^{2} + 4 \sqrt{2 } x + 3\sqrt{2}x + 4 \\ {2x} (3x+ 2 \sqrt{2} ) + \sqrt{2} (3x + 2 \sqrt{2} ) \\ x = \frac{ \sqrt{2} }{2} and \frac{2 \sqrt{2} }{3}$

.......hop it will be helpful