Question

$6x^{2} +7x-3$

Answer 1

Answer:

$6 {x}^{2} + 7x - 3 = 0$

$6 {x}^{2} - 2x + 9x - 3 = 0$

$2x(3x - 1) + 3(3x - 1) = 0$

$(2x + 3)(3x - 1) = 0$

$either \: 2x + 3 = 0 \: or \: 3x - 1 = 0$

$if \: 2x + 3 = 0 \\ 2x = - 3 \\ x = \frac{ - 3}{2}$

$if \: 3x - 1 = 0 \\ 3x = 1 \\ x = \frac{1}{ 3}$

$x = \frac{ - 3}{2} or \: x = \frac{1}{3}$