Math, asked by SSKP, 6 months ago


6x {}^{2}  + 7x - 5

Answers

Answered by Anonymous
305

Step-by-step explanation:

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6x {}^{2} + 7x - 5

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6 {x}^{2}  + 7x - 5 = 0

6 {x}^{2}  + 10x - 3x - 5 = 0

⟹2x(3x + 5) - 1(3x + 5) = 0

⟹(2x - 1)(3x + 5) = 0

x =  \frac{1}{2}

x =  -  \frac{5}{3}

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Answered by tonystarkironman94
2

Answer:

6 {x}^{2}  + 7x - 5 \\ 6 {x}^{2}  + (10 - 3)x - 5 \\ 6 {x}^{2}  + 10x - 3x - 5 \\ 2x(3x + 5) - 1(3x + 5) \\ (3x + 5)(2x - 1)

x=1/2or-5/3

this is your answer

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