Question

${7}^{2} + \frac{7x}{2} + \frac{3}{4}$
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Answer 1

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${7}^{2} + \frac{7x}{2} + \frac{3}{4}$

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${7}^{2} + \frac{7x}{2} + \frac{3}{4} = \frac{4 \times 49 + 14x + 3}{4}$

$= \frac{196 + 14x + 3}{4} = \frac{199 + 14x}{4}$

$199 + 14x = 0$

$14x = - 199$

$x = - \frac{199}{14} = 14.21$

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