Question

$7 {}^{8} \div (7 {}^{5} \times 7 {}^{3})$
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Answer 1

Answer:

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Answer 2

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Explanation:

${7}^{8} \div ( {7}^{5} \times {7}^{3} )$

$= > {7}^{8} \div ( {7}^{5 + 3} )$

$= > {7}^{8} \div {7}^{8}$

$= > \frac{ {7}^{8} }{ {7}^{8} } = {7}^{8 - 8} = {7}^{0} = 1$

Concept used :-

• value with same base of different power when multiply then their power gets added and in division their power gets subtracted.
• Value of zero power will be considered as 1