Question

$7 \sqrt{3x { }^{2} } - 25x + 4 \sqrt{3}$
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Answer 1

Answer:

Given :

p ( x ) = 7 √ 3 x² - 25 x + 4 √ 3

= > 7 √ 3 x² - 21 x - 4 x + 4 √ 3

= > 7 √ 3 x ( x -  √ 3 ) - 4 ( x - √ 3 )

= > ( x - √ 3 ) ( 7 √ 3 x - 4 ) .

Zeroes of p ( x ) :

x - √ 3 = 0

x = √ 3

OR

7 √ 3 x - 4 = 0

x = 4 /  7 √ 3.